2y+2(y-4)=8y-6(y-10)

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Solution for 2y+2(y-4)=8y-6(y-10) equation: 



2y+2(y-4)=8y-6(y-10)

We move all terms to the left:

2y+2(y-4)-(8y-6(y-10))=0

We multiply parentheses

2y+2y-(8y-6(y-10))-8=0



We calculate terms in parentheses: -(8y-6(y-10)), so:

8y-6(y-10)

We multiply parentheses

8y-6y+60

We add all the numbers together, and all the variables

2y+60

Back to the equation:

-(2y+60)



We add all the numbers together, and all the variables

4y-(2y+60)-8=0

We get rid of parentheses

4y-2y-60-8=0

We add all the numbers together, and all the variables

2y-68=0

We move all terms containing y to the left, all other terms to the right

2y=68

y=68/2

y=34

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