2y+2(y/2)=32

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Solution for 2y+2(y/2)=32 equation:



2y+2(y/2)=32
We move all terms to the left:
2y+2(y/2)-(32)=0
We add all the numbers together, and all the variables
2y+2(+y/2)-32=0
We multiply parentheses
2y+2y-32=0
We add all the numbers together, and all the variables
4y-32=0
We move all terms containing y to the left, all other terms to the right
4y=32
y=32/4
y=8

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