2y+22=4(y+1)

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Solution for 2y+22=4(y+1) equation: 



2y+22=4(y+1)

We move all terms to the left:

2y+22-(4(y+1))=0



We calculate terms in parentheses: -(4(y+1)), so:

4(y+1)

We multiply parentheses

4y+4

Back to the equation:

-(4y+4)



We get rid of parentheses

2y-4y-4+22=0

We add all the numbers together, and all the variables

-2y+18=0

We move all terms containing y to the left, all other terms to the right

-2y=-18

y=-18/-2

y=+9

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