2y+25+62+3y=-20y-3-10

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Solution for 2y+25+62+3y=-20y-3-10 equation: 



2y+25+62+3y=-20y-3-10

We move all terms to the left:

2y+25+62+3y-(-20y-3-10)=0

We add all the numbers together, and all the variables

2y+3y-(-20y-13)+25+62=0

We add all the numbers together, and all the variables

5y-(-20y-13)+87=0

We get rid of parentheses

5y+20y+13+87=0

We add all the numbers together, and all the variables

25y+100=0

We move all terms containing y to the left, all other terms to the right

25y=-100

y=-100/25

y=-4

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