2y+28=18y+12

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Solution for 2y+28=18y+12 equation: 



2y+28=18y+12

We move all terms to the left:

2y+28-(18y+12)=0

We get rid of parentheses

2y-18y-12+28=0

We add all the numbers together, and all the variables

-16y+16=0

We move all terms containing y to the left, all other terms to the right

-16y=-16

y=-16/-16

y=1

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