2y+3(6y+7)=4y+5(3y+2)

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Solution for 2y+3(6y+7)=4y+5(3y+2) equation:



2y+3(6y+7)=4y+5(3y+2)
We move all terms to the left:
2y+3(6y+7)-(4y+5(3y+2))=0
We multiply parentheses
2y+18y-(4y+5(3y+2))+21=0
We calculate terms in parentheses: -(4y+5(3y+2)), so:
4y+5(3y+2)
We multiply parentheses
4y+15y+10
We add all the numbers together, and all the variables
19y+10
Back to the equation:
-(19y+10)
We add all the numbers together, and all the variables
20y-(19y+10)+21=0
We get rid of parentheses
20y-19y-10+21=0
We add all the numbers together, and all the variables
y+11=0
We move all terms containing y to the left, all other terms to the right
y=-11

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