2y+3(y+2)=27

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Solution for 2y+3(y+2)=27 equation: 



2y+3(y+2)=27

We move all terms to the left:

2y+3(y+2)-(27)=0

We multiply parentheses

2y+3y+6-27=0

We add all the numbers together, and all the variables

5y-21=0

We move all terms containing y to the left, all other terms to the right

5y=21

y=21/5

y=4+1/5

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