2y+3+3x-3+z=2y+3x+z

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Solution for 2y+3+3x-3+z=2y+3x+z equation: 


Simplifying
2y + 3 + 3x + -3 + z = 2y + 3x + z

Reorder the terms:
3 + -3 + 3x + 2y + z = 2y + 3x + z

Combine like terms: 3 + -3 = 0
0 + 3x + 2y + z = 2y + 3x + z
3x + 2y + z = 2y + 3x + z

Reorder the terms:
3x + 2y + z = 3x + 2y + z

Add '-3x' to each side of the equation.
3x + 2y + -3x + z = 3x + 2y + -3x + z

Reorder the terms:
3x + -3x + 2y + z = 3x + 2y + -3x + z

Combine like terms: 3x + -3x = 0
0 + 2y + z = 3x + 2y + -3x + z
2y + z = 3x + 2y + -3x + z

Reorder the terms:
2y + z = 3x + -3x + 2y + z

Combine like terms: 3x + -3x = 0
2y + z = 0 + 2y + z
2y + z = 2y + z

Add '-2y' to each side of the equation.
2y + -2y + z = 2y + -2y + z

Combine like terms: 2y + -2y = 0
0 + z = 2y + -2y + z
z = 2y + -2y + z

Combine like terms: 2y + -2y = 0
z = 0 + z
z = z

Add '-1z' to each side of the equation.
z + -1z = z + -1z

Combine like terms: z + -1z = 0
0 = z + -1z

Combine like terms: z + -1z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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