2y+3/2y-4=y-1/y-2

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Solution for 2y+3/2y-4=y-1/y-2 equation: 



2y+3/2y-4=y-1/y-2

We move all terms to the left:

2y+3/2y-4-(y-1/y-2)=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R





Domain of the equation: y-2)!=0

y∈R



We get rid of parentheses

2y+3/2y-y+1/y+2-4=0

We calculate fractions


2y-y+3y/2y^2+2y/2y^2+2-4=0

We add all the numbers together, and all the variables

y+3y/2y^2+2y/2y^2-2=0

We multiply all the terms by the denominator


y*2y^2+3y+2y-2*2y^2=0

We add all the numbers together, and all the variables

5y+y*2y^2-2*2y^2=0

Wy multiply elements

2y^3-4y^2+5y=0

We do not support eypression: y^3

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