2y+3/3y+2=4y+5/6y+7

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Solution for 2y+3/3y+2=4y+5/6y+7 equation:



2y+3/3y+2=4y+5/6y+7
We move all terms to the left:
2y+3/3y+2-(4y+5/6y+7)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 6y+7)!=0
y∈R
We get rid of parentheses
2y+3/3y-4y-5/6y-7+2=0
We calculate fractions
2y-4y+18y/18y^2+(-15y)/18y^2-7+2=0
We add all the numbers together, and all the variables
-2y+18y/18y^2+(-15y)/18y^2-5=0
We multiply all the terms by the denominator
-2y*18y^2+18y+(-15y)-5*18y^2=0
We add all the numbers together, and all the variables
18y-2y*18y^2+(-15y)-5*18y^2=0
Wy multiply elements
-36y^3-90y^2+18y+(-15y)=0
We get rid of parentheses
-36y^3-90y^2+18y-15y=0
We do not support eypression: y^3

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