2y+3/7+y-1/3=3y-2

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Solution for 2y+3/7+y-1/3=3y-2 equation: 



2y+3/7+y-1/3=3y-2

We move all terms to the left:

2y+3/7+y-1/3-(3y-2)=0

We add all the numbers together, and all the variables

3y-(3y-2)+3/7-1/3=0

We get rid of parentheses

3y-3y+2+3/7-1/3=0

We calculate fractions

There is no solution for this equation

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