2y+32=-5(y+2)

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Solution for 2y+32=-5(y+2) equation: 



2y+32=-5(y+2)

We move all terms to the left:

2y+32-(-5(y+2))=0



We calculate terms in parentheses: -(-5(y+2)), so:

-5(y+2)

We multiply parentheses

-5y-10

Back to the equation:

-(-5y-10)



We get rid of parentheses

2y+5y+10+32=0

We add all the numbers together, and all the variables

7y+42=0

We move all terms containing y to the left, all other terms to the right

7y=-42

y=-42/7

y=-6

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