2y+33+4y-68=3y-42

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Solution for 2y+33+4y-68=3y-42 equation: 



2y+33+4y-68=3y-42

We move all terms to the left:

2y+33+4y-68-(3y-42)=0

We add all the numbers together, and all the variables

6y-(3y-42)-35=0

We get rid of parentheses

6y-3y+42-35=0

We add all the numbers together, and all the variables

3y+7=0

We move all terms containing y to the left, all other terms to the right

3y=-7

y=-7/3

y=-2+1/3

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