2y+35=-3(y+5)

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Solution for 2y+35=-3(y+5) equation: 



2y+35=-3(y+5)

We move all terms to the left:

2y+35-(-3(y+5))=0



We calculate terms in parentheses: -(-3(y+5)), so:

-3(y+5)

We multiply parentheses

-3y-15

Back to the equation:

-(-3y-15)



We get rid of parentheses

2y+3y+15+35=0

We add all the numbers together, and all the variables

5y+50=0

We move all terms containing y to the left, all other terms to the right

5y=-50

y=-50/5

y=-10

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