2y+35=-3(y+5)

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Solution for 2y+35=-3(y+5) equation:



2y+35=-3(y+5)
We move all terms to the left:
2y+35-(-3(y+5))=0
We calculate terms in parentheses: -(-3(y+5)), so:
-3(y+5)
We multiply parentheses
-3y-15
Back to the equation:
-(-3y-15)
We get rid of parentheses
2y+3y+15+35=0
We add all the numbers together, and all the variables
5y+50=0
We move all terms containing y to the left, all other terms to the right
5y=-50
y=-50/5
y=-10

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