2y+36=8(y+3)

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Solution for 2y+36=8(y+3) equation: 



2y+36=8(y+3)

We move all terms to the left:

2y+36-(8(y+3))=0



We calculate terms in parentheses: -(8(y+3)), so:

8(y+3)

We multiply parentheses

8y+24

Back to the equation:

-(8y+24)



We get rid of parentheses

2y-8y-24+36=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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