2y+3=2(6y-1)

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Solution for 2y+3=2(6y-1) equation: 



2y+3=2(6y-1)

We move all terms to the left:

2y+3-(2(6y-1))=0



We calculate terms in parentheses: -(2(6y-1)), so:

2(6y-1)

We multiply parentheses

12y-2

Back to the equation:

-(12y-2)



We get rid of parentheses

2y-12y+2+3=0

We add all the numbers together, and all the variables

-10y+5=0

We move all terms containing y to the left, all other terms to the right

-10y=-5

y=-5/-10

y=1/2

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