2y+3=3(y+2)

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Solution for 2y+3=3(y+2) equation:



2y+3=3(y+2)
We move all terms to the left:
2y+3-(3(y+2))=0
We calculate terms in parentheses: -(3(y+2)), so:
3(y+2)
We multiply parentheses
3y+6
Back to the equation:
-(3y+6)
We get rid of parentheses
2y-3y-6+3=0
We add all the numbers together, and all the variables
-1y-3=0
We move all terms containing y to the left, all other terms to the right
-y=3
y=3/-1
y=-3

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