2y+3=4y+1=y+5

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Solution for 2y+3=4y+1=y+5 equation: 



2y+3=4y+1=y+5

We move all terms to the left:

2y+3-(4y+1)=0

We get rid of parentheses

2y-4y-1+3=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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