2y+4(3y-8)=108

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Solution for 2y+4(3y-8)=108 equation: 



2y+4(3y-8)=108

We move all terms to the left:

2y+4(3y-8)-(108)=0

We multiply parentheses

2y+12y-32-108=0

We add all the numbers together, and all the variables

14y-140=0

We move all terms containing y to the left, all other terms to the right

14y=140

y=140/14

y=10

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