2y+4+3(y-7)=4(y+1)

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Solution for 2y+4+3(y-7)=4(y+1) equation:



2y+4+3(y-7)=4(y+1)
We move all terms to the left:
2y+4+3(y-7)-(4(y+1))=0
We multiply parentheses
2y+3y-(4(y+1))-21+4=0
We calculate terms in parentheses: -(4(y+1)), so:
4(y+1)
We multiply parentheses
4y+4
Back to the equation:
-(4y+4)
We add all the numbers together, and all the variables
5y-(4y+4)-17=0
We get rid of parentheses
5y-4y-4-17=0
We add all the numbers together, and all the variables
y-21=0
We move all terms containing y to the left, all other terms to the right
y=21

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