2y+40=4(y+7)

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Solution for 2y+40=4(y+7) equation: 



2y+40=4(y+7)

We move all terms to the left:

2y+40-(4(y+7))=0



We calculate terms in parentheses: -(4(y+7)), so:

4(y+7)

We multiply parentheses

4y+28

Back to the equation:

-(4y+28)



We get rid of parentheses

2y-4y-28+40=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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