2y+41=5(y+4)

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Solution for 2y+41=5(y+4) equation: 



2y+41=5(y+4)

We move all terms to the left:

2y+41-(5(y+4))=0



We calculate terms in parentheses: -(5(y+4)), so:

5(y+4)

We multiply parentheses

5y+20

Back to the equation:

-(5y+20)



We get rid of parentheses

2y-5y-20+41=0

We add all the numbers together, and all the variables

-3y+21=0

We move all terms containing y to the left, all other terms to the right

-3y=-21

y=-21/-3

y=+7

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