2y+42+2y=8y-18

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Solution for 2y+42+2y=8y-18 equation: 



2y+42+2y=8y-18

We move all terms to the left:

2y+42+2y-(8y-18)=0

We add all the numbers together, and all the variables

4y-(8y-18)+42=0

We get rid of parentheses

4y-8y+18+42=0

We add all the numbers together, and all the variables

-4y+60=0

We move all terms containing y to the left, all other terms to the right

-4y=-60

y=-60/-4

y=+15

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