2y+42=-4(y-3)

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Solution for 2y+42=-4(y-3) equation: 



2y+42=-4(y-3)

We move all terms to the left:

2y+42-(-4(y-3))=0



We calculate terms in parentheses: -(-4(y-3)), so:

-4(y-3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

2y+4y-12+42=0

We add all the numbers together, and all the variables

6y+30=0

We move all terms containing y to the left, all other terms to the right

6y=-30

y=-30/6

y=-5

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