2y+4=-2(3y+10)

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Solution for 2y+4=-2(3y+10) equation: 



2y+4=-2(3y+10)

We move all terms to the left:

2y+4-(-2(3y+10))=0



We calculate terms in parentheses: -(-2(3y+10)), so:

-2(3y+10)

We multiply parentheses

-6y-20

Back to the equation:

-(-6y-20)



We get rid of parentheses

2y+6y+20+4=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

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