2y+4=3(y-2)

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Solution for 2y+4=3(y-2) equation: 



2y+4=3(y-2)

We move all terms to the left:

2y+4-(3(y-2))=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

2y-3y+6+4=0

We add all the numbers together, and all the variables

-1y+10=0

We move all terms containing y to the left, all other terms to the right

-y=-10

y=-10/-1

y=+10

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