2y+5/y=1/3+y

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Solution for 2y+5/y=1/3+y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2*y+5/y = y+1/3 // - y+1/3

2*y-y+5/y-(1/3) = 0

2*y-y+5/y-1/3 = 0

1*y^1+5*y^-1-1/3*y^0 = 0

(1*y^2-1/3*y^1+5*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2-1/3*y^1+5*y^0) = 0

y^1

y^2+(-1/3)*y+5 = 0

y^2+(-1/3)*y+5 = 0

DELTA = (-1/3)^2-(1*4*5)

DELTA = -179/9

DELTA < 0

y in { } 

y belongs to the empty set

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