2y+5=15-(4+5y)

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Solution for 2y+5=15-(4+5y) equation: 



2y+5=15-(4+5y)

We move all terms to the left:

2y+5-(15-(4+5y))=0

We add all the numbers together, and all the variables

2y-(15-(5y+4))+5=0



We calculate terms in parentheses: -(15-(5y+4)), so:

15-(5y+4)

determiningTheFunctionDomain
-(5y+4)+15

We get rid of parentheses

-5y-4+15

We add all the numbers together, and all the variables

-5y+11

Back to the equation:

-(-5y+11)



We get rid of parentheses

2y+5y-11+5=0

We add all the numbers together, and all the variables

7y-6=0

We move all terms containing y to the left, all other terms to the right

7y=6

y=6/7

y=6/7

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