2y+5=15-(4+5y)

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Solution for 2y+5=15-(4+5y) equation:



2y+5=15-(4+5y)
We move all terms to the left:
2y+5-(15-(4+5y))=0
We add all the numbers together, and all the variables
2y-(15-(5y+4))+5=0
We calculate terms in parentheses: -(15-(5y+4)), so:
15-(5y+4)
determiningTheFunctionDomain -(5y+4)+15
We get rid of parentheses
-5y-4+15
We add all the numbers together, and all the variables
-5y+11
Back to the equation:
-(-5y+11)
We get rid of parentheses
2y+5y-11+5=0
We add all the numbers together, and all the variables
7y-6=0
We move all terms containing y to the left, all other terms to the right
7y=6
y=6/7
y=6/7

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