2y+5=2(3y+4)-(5-y)

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Solution for 2y+5=2(3y+4)-(5-y) equation: 



2y+5=2(3y+4)-(5-y)

We move all terms to the left:

2y+5-(2(3y+4)-(5-y))=0

We add all the numbers together, and all the variables

2y-(2(3y+4)-(-1y+5))+5=0



We calculate terms in parentheses: -(2(3y+4)-(-1y+5)), so:

2(3y+4)-(-1y+5)

We multiply parentheses

6y-(-1y+5)+8

We get rid of parentheses

6y+1y-5+8

We add all the numbers together, and all the variables

7y+3

Back to the equation:

-(7y+3)



We get rid of parentheses

2y-7y-3+5=0

We add all the numbers together, and all the variables

-5y+2=0

We move all terms containing y to the left, all other terms to the right

-5y=-2

y=-2/-5

y=2/5

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