2y+6(y+3)=36

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Solution for 2y+6(y+3)=36 equation: 



2y+6(y+3)=36

We move all terms to the left:

2y+6(y+3)-(36)=0

We multiply parentheses

2y+6y+18-36=0

We add all the numbers together, and all the variables

8y-18=0

We move all terms containing y to the left, all other terms to the right

8y=18

y=18/8

y=2+1/4

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