2y+6+3y=2(2y-6)+7

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Solution for 2y+6+3y=2(2y-6)+7 equation: 



2y+6+3y=2(2y-6)+7

We move all terms to the left:

2y+6+3y-(2(2y-6)+7)=0

We add all the numbers together, and all the variables

5y-(2(2y-6)+7)+6=0



We calculate terms in parentheses: -(2(2y-6)+7), so:

2(2y-6)+7

We multiply parentheses

4y-12+7

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)



We get rid of parentheses

5y-4y+5+6=0

We add all the numbers together, and all the variables

y+11=0

We move all terms containing y to the left, all other terms to the right

y=-11

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