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2y+6=2(y-5)
We move all terms to the left:
2y+6-(2(y-5))=0
We calculate terms in parentheses: -(2(y-5)), so:We get rid of parentheses
2(y-5)
We multiply parentheses
2y-10
Back to the equation:
-(2y-10)
2y-2y+10+6=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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