2y+8-2(-7y-4)=2(y-1)

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Solution for 2y+8-2(-7y-4)=2(y-1) equation: 



2y+8-2(-7y-4)=2(y-1)

We move all terms to the left:

2y+8-2(-7y-4)-(2(y-1))=0

We multiply parentheses

2y+14y-(2(y-1))+8+8=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

16y-(2y-2)+16=0

We get rid of parentheses

16y-2y+2+16=0

We add all the numbers together, and all the variables

14y+18=0

We move all terms containing y to the left, all other terms to the right

14y=-18

y=-18/14

y=-1+2/7

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