2y+9(y+3)=11y+27

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Solution for 2y+9(y+3)=11y+27 equation: 



2y+9(y+3)=11y+27

We move all terms to the left:

2y+9(y+3)-(11y+27)=0

We multiply parentheses

2y+9y-(11y+27)+27=0

We get rid of parentheses

2y+9y-11y-27+27=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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