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2y-(1-2y)=5-3(1+y)
We move all terms to the left:
2y-(1-2y)-(5-3(1+y))=0
We add all the numbers together, and all the variables
2y-(-2y+1)-(5-3(y+1))=0
We get rid of parentheses
2y+2y-(5-3(y+1))-1=0
We calculate terms in parentheses: -(5-3(y+1)), so:We add all the numbers together, and all the variables
5-3(y+1)
determiningTheFunctionDomain -3(y+1)+5
We multiply parentheses
-3y-3+5
We add all the numbers together, and all the variables
-3y+2
Back to the equation:
-(-3y+2)
4y-(-3y+2)-1=0
We get rid of parentheses
4y+3y-2-1=0
We add all the numbers together, and all the variables
7y-3=0
We move all terms containing y to the left, all other terms to the right
7y=3
y=3/7
y=3/7
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