2y-(3y+2)-6+(3y-8)=y

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Solution for 2y-(3y+2)-6+(3y-8)=y equation: 



2y-(3y+2)-6+(3y-8)=y

We move all terms to the left:

2y-(3y+2)-6+(3y-8)-(y)=0

We add all the numbers together, and all the variables

y-(3y+2)+(3y-8)-6=0

We get rid of parentheses

y-3y+3y-2-8-6=0

We add all the numbers together, and all the variables

y-16=0

We move all terms containing y to the left, all other terms to the right

y=16

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