2y-(3y/5)=(3y/5)

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Solution for 2y-(3y/5)=(3y/5) equation: 



2y-(3y/5)=(3y/5)

We move all terms to the left:

2y-(3y/5)-((3y/5))=0

We add all the numbers together, and all the variables

2y-(+3y/5)-((+3y/5))=0

We get rid of parentheses

2y-3y/5-((+3y/5))=0

We calculate fractions


2y=0

y=0/2

y=0

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