2y-(6y+5)=5(y+4)-2y

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Solution for 2y-(6y+5)=5(y+4)-2y equation: 



2y-(6y+5)=5(y+4)-2y

We move all terms to the left:

2y-(6y+5)-(5(y+4)-2y)=0

We get rid of parentheses

2y-6y-(5(y+4)-2y)-5=0



We calculate terms in parentheses: -(5(y+4)-2y), so:

5(y+4)-2y

We add all the numbers together, and all the variables

-2y+5(y+4)

We multiply parentheses

-2y+5y+20

We add all the numbers together, and all the variables

3y+20

Back to the equation:

-(3y+20)



We add all the numbers together, and all the variables

-4y-(3y+20)-5=0

We get rid of parentheses

-4y-3y-20-5=0

We add all the numbers together, and all the variables

-7y-25=0

We move all terms containing y to the left, all other terms to the right

-7y=25

y=25/-7

y=-3+4/7

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