2y-1+2(3y+2)=-4(y+3)

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Solution for 2y-1+2(3y+2)=-4(y+3) equation: 



2y-1+2(3y+2)=-4(y+3)

We move all terms to the left:

2y-1+2(3y+2)-(-4(y+3))=0

We multiply parentheses

2y+6y-(-4(y+3))+4-1=0



We calculate terms in parentheses: -(-4(y+3)), so:

-4(y+3)

We multiply parentheses

-4y-12

Back to the equation:

-(-4y-12)



We add all the numbers together, and all the variables

8y-(-4y-12)+3=0

We get rid of parentheses

8y+4y+12+3=0

We add all the numbers together, and all the variables

12y+15=0

We move all terms containing y to the left, all other terms to the right

12y=-15

y=-15/12

y=-1+1/4

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