2y-10=-2(5-y)

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Solution for 2y-10=-2(5-y) equation: 



2y-10=-2(5-y)

We move all terms to the left:

2y-10-(-2(5-y))=0

We add all the numbers together, and all the variables

2y-(-2(-1y+5))-10=0



We calculate terms in parentheses: -(-2(-1y+5)), so:

-2(-1y+5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

2y-2y+10-10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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