2y-10=40+8y

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Solution for 2y-10=40+8y equation: 



2y-10=40+8y

We move all terms to the left:

2y-10-(40+8y)=0

We add all the numbers together, and all the variables

2y-(8y+40)-10=0

We get rid of parentheses

2y-8y-40-10=0

We add all the numbers together, and all the variables

-6y-50=0

We move all terms containing y to the left, all other terms to the right

-6y=50

y=50/-6

y=-8+1/3

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