2y-12=-8(y-6)

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Solution for 2y-12=-8(y-6) equation: 



2y-12=-8(y-6)

We move all terms to the left:

2y-12-(-8(y-6))=0



We calculate terms in parentheses: -(-8(y-6)), so:

-8(y-6)

We multiply parentheses

-8y+48

Back to the equation:

-(-8y+48)



We get rid of parentheses

2y+8y-48-12=0

We add all the numbers together, and all the variables

10y-60=0

We move all terms containing y to the left, all other terms to the right

10y=60

y=60/10

y=6

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