2y-2(6-y)=6(3y+2)

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Solution for 2y-2(6-y)=6(3y+2) equation: 



2y-2(6-y)=6(3y+2)

We move all terms to the left:

2y-2(6-y)-(6(3y+2))=0

We add all the numbers together, and all the variables

2y-2(-1y+6)-(6(3y+2))=0

We multiply parentheses

2y+2y-(6(3y+2))-12=0



We calculate terms in parentheses: -(6(3y+2)), so:

6(3y+2)

We multiply parentheses

18y+12

Back to the equation:

-(18y+12)



We add all the numbers together, and all the variables

4y-(18y+12)-12=0

We get rid of parentheses

4y-18y-12-12=0

We add all the numbers together, and all the variables

-14y-24=0

We move all terms containing y to the left, all other terms to the right

-14y=24

y=24/-14

y=-1+5/7

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