2y-28=-2(y+6)

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Solution for 2y-28=-2(y+6) equation: 



2y-28=-2(y+6)

We move all terms to the left:

2y-28-(-2(y+6))=0



We calculate terms in parentheses: -(-2(y+6)), so:

-2(y+6)

We multiply parentheses

-2y-12

Back to the equation:

-(-2y-12)



We get rid of parentheses

2y+2y+12-28=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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