2y-28=6(y+2)

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Solution for 2y-28=6(y+2) equation: 



2y-28=6(y+2)

We move all terms to the left:

2y-28-(6(y+2))=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

2y-6y-12-28=0

We add all the numbers together, and all the variables

-4y-40=0

We move all terms containing y to the left, all other terms to the right

-4y=40

y=40/-4

y=-10

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