2y-2=(3y-11)2

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Solution for 2y-2=(3y-11)2 equation: 



2y-2=(3y-11)2

We move all terms to the left:

2y-2-((3y-11)2)=0



We calculate terms in parentheses: -((3y-11)2), so:

(3y-11)2

We multiply parentheses

6y-22

Back to the equation:

-(6y-22)



We get rid of parentheses

2y-6y+22-2=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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