2y-2=3y-(6-12)

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Solution for 2y-2=3y-(6-12) equation: 



2y-2=3y-(6-12)

We move all terms to the left:

2y-2-(3y-(6-12))=0

We add all the numbers together, and all the variables

2y-(3y-(-6))-2=0



We calculate terms in parentheses: -(3y-(-6)), so:

3y-(-6)

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

2y-3y-6-2=0

We add all the numbers together, and all the variables

-1y-8=0

We move all terms containing y to the left, all other terms to the right

-y=8

y=8/-1

y=-8

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