2y-2=4(y-2)

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Solution for 2y-2=4(y-2) equation: 



2y-2=4(y-2)

We move all terms to the left:

2y-2-(4(y-2))=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

2y-4y+8-2=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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