2y-3(10-2y)/4-3+5y/2=6

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Solution for 2y-3(10-2y)/4-3+5y/2=6 equation: 


y in (-oo:+oo)

2*y-((3*(10-(2*y)))/4)+(5*y)/2-3 = 6 // - 6

2*y-((3*(10-(2*y)))/4)+(5*y)/2-6-3 = 0

(-3/4)*(10-2*y)+2*y+(5*y)/2-6-3 = 0

2*y-3/4*(10-2*y)+(5*y)/2-6-3 = 0

(-3/4*2*(10-2*y))/2+(2*2*y)/2+(5*y)/2+(-6*2)/2+(-3*2)/2 = 0

2*2*y-3/4*2*(10-2*y)+5*y-6*2-3*2 = 0

7*y+5*y-15-12-6 = 0

12*y-15-12-6 = 0

12*y-27-6 = 0

12*y-33 = 0

(12*y-33)/2 = 0

(12*y-33)/2 = 0 // * 2

12*y-33 = 0

12*y-33 = 0 // + 33

12*y = 33 // : 12

y = 33/12

y = 11/4

y = 11/4

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