2y-3(4y-5)=35

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Solution for 2y-3(4y-5)=35 equation: 



2y-3(4y-5)=35

We move all terms to the left:

2y-3(4y-5)-(35)=0

We multiply parentheses

2y-12y+15-35=0

We add all the numbers together, and all the variables

-10y-20=0

We move all terms containing y to the left, all other terms to the right

-10y=20

y=20/-10

y=-2

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